A wood column is pin connected at its top and bottom. Determine the controlling slenderness ratio, le/d, for the column. Assume normal temperatures, no incising, and that all loads are downward. Ignore the weight of the member.Load:PD = 2,500 lbPL = 1,000 lbPLr = 500 lbPS = 5,000 lbPR = 3,500 lbPW = 4,500 lbPE = 0 lbLength:L = 12 ftMember size:4 x 6Stress grade and species:Select Structural Douglas Fir-LarchUnbraced length:lu = L = 12 ftMoisture content:MC < 19 percent

A wood column is pin connected at its top and bottom. Determine the controlling slenderness ratio, le/d, for the column. Assume normal temperatures, no incising, and that all loads are downward. Ignore the weight of the member.Load:PD = 3,000 lbPL = 1,500 lbPLr = 0 lbPS = 4,500 lbPR = 1,000 lbPW = 3,000 lbPE = 0 lbLength:L = 9 ftMember size:4 x 14Stress grade and species:No. 1 & Better Douglas Fir-LarchUnbraced length:lu = L = 9 ftMoisture content:MC < 19 percent

A wood member is loaded as shown. Using ASD, determine the adjusted tension strength, Ft’. Assume normal temperatures, no incising, and that all loads act in the directions shown. Ignore the weight of the member.Load:PD = 2,500 lbPL = 0 lbPLr = 0 lbPS = 0 lbPR = 0 lbPW = 5,500 lbPE = 7,000 lbQD = 0 lbQL = 500 lbQLr = 5,000 lbQS = 3,000 lbQR = 4,500 lbQW = 0 lbQE = 0 lbSpan:L = 14 ft Member size:4 x 8 Stress grade and species:No. 1 Douglas Fir-Larch Unbraced length:lu = L/2 = 7 ft Moisture content:MC < 19 percent 

Determine the dowel bearing strength for a 1/2-in.-diameter bolt in Southern Pine with the load applied parallel to grain.

Use APA Technical Note Q225 entitled Load-Span Tables for APA Structural-Use Panels and ASD procedures to answer the following question.The spacing of joists in a flat roof is 16-in. o.c. Roof dead load = 10 psf. Snow load = 36 psf. Roof sheathing is to be an APA rated plywood sheathing, and panels are to be oriented in the strong direction. The load is governed by deflection limits of L/240 for snow load and L/180 for total load. Only consider these limits. Assume multi-span, normal duration of load, dry conditions, and panels 24 inches or wider. Would a panel with a span rating of 32/16 be adequate?

A wood member is loaded as shown. Using ASD, determine the adjusted bending strength, Fb’. Assume normal temperatures, no incising, and that all loads act in the directions shown. Ignore the weight of the member.Load:PD = 2,500 lbPL = 0 lbPLr = 0 lbPS = 0 lbPR = 0 lbPW = 9,000 lbPE = 5,000 lbQD = 3,000 lbQL = 4,000 lbQLr = 5,000 lbQS = 1,000 lbQR = 1,000 lbQW = 0 lbQE = 0 lbSpan:L = 14 ft Member size:4 x 10 Stress grade and species:Select Structural Douglas Fir-Larch Unbraced length:lu = 0 ft Moisture content:MC < 19 percent 

A wood member is loaded as shown. Using ASD, determine the maximum bending stress in the member. Assume normal temperatures, no incising, and that all loads act in the directions shown. Ignore the weight of the member.Load:PD = 3,500 lbPL = 0 lbPLr = 0 lbPS = 0 lbPR = 0 lbPW = 6,000 lbPE = 6,500 lbQD = 1,500 lbQL = 2,500 lbQLr = 1,000 lbQS = 1,000 lbQR = 1,000 lbQW = 0 lbQE = 0 lbSpan:L = 7 ft Member size:4 x 8 Stress grade and species:Select Structural Douglas Fir-Larch Unbraced length:lu = L/2 = 3.5 ft Moisture content:MC < 19 percent 

Use APA Technical Note Q225 entitled Load-Span Tables for APA Structural-Use Panels and ASD procedures to answer the following question.The spacing of joists in a flat roof is 24-in. o.c. Roof dead load = 10 psf. Snow load = 70 psf. Roof sheathing is to be an APA rated plywood STRUCTURAL I sheathing, and panels are to be oriented in the weak direction. The load is governed by deflection limits of L/360 for snow load and L/240 for total load. Only consider these limits. Assume multi-span, normal duration of load, dry conditions, and panels 24 inches or wider. Would a panel with a span rating of 32/16 be adequate?

A wood member is loaded as shown. Using ASD, determine the adjusted tension strength, Ft’. Assume normal temperatures, no incising, and that all loads act in the directions shown. Ignore the weight of the member.Load:PD = 5,000 lbPL = 0 lbPLr = 0 lbPS = 0 lbPR = 0 lbPW = 5,500 lbPE = 9,000 lbQD = 500 lbQL = 5,000 lbQLr = 2,500 lbQS = 4,000 lbQR = 0 lbQW = 0 lbQE = 0 lbSpan:L = 14 ft Member size:4 x 14 Stress grade and species:No. 2 Douglas Fir-Larch Unbraced length:lu = L/2 = 7 ft Moisture content:MC < 19 percent 

A wood member is loaded as shown. Using ASD, determine the adjusted bending strength, Fb’. Assume normal temperatures, no incising, and that all loads act in the directions shown. Ignore the weight of the member.Load:PD = 4,500 lbPL = 0 lbPLr = 0 lbPS = 0 lbPR = 0 lbPW = 7,500 lbPE = 9,000 lbQD = 2,500 lbQL = 3,500 lbQLr = 4,500 lbQS = 500 lbQR = 1,000 lbQW = 0 lbQE = 0 lbSpan:L = 8 ft Member size:4 x 12 Stress grade and species:No. 1 & Better Douglas Fir-Larch Unbraced length:lu = 0 ft Moisture content:MC > 19 percent