A wood member is loaded as shown. Using ASD, determine the m…

A wood member is loaded as shown. Using ASD, determine the maximum axial stress in the member. Assume normal temperatures, no incising, and that all loads act in the directions shown. Ignore the weight of the member.Load:PD = 2,500 lbPL = 0 lbPLr = 0 lbPS = 0 lbPR = 0 lbPW = 9,000 lbPE = 6,500 lbQD = 2,000 lbQL = 2,500 lbQLr = 1,000 lbQS = 2,000 lbQR = 1,000 lbQW = 0 lbQE = 0 lbSpan:L = 10 ft Member size:4 x 10 Stress grade and species:No. 1 Douglas Fir-Larch Unbraced length:lu = L/2 = 5 ft Moisture content:MC < 19 percent 

Determine the ASD adjusted design compression strength paral…

Determine the ASD adjusted design compression strength parallel to grain, Fc’, for the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:wD = 200 lb/ftwLr = 330 lb/ftLoad combination:D + LrSpan:L = 6 ftMember size:4 x 10Stress grade and species:Select Structural Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC < 19 percentLive load deflection limit:Allow. Δ ≤ L/360

Determine the ASD adjusted minimum modulus of elasticity, Em…

Determine the ASD adjusted minimum modulus of elasticity, Emin’, for the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:PD = 520 lbPLr = 1,600 lbLoad combination:D + LrSpan:L = 12 ftMember size:4 x 12Stress grade and species:No. 2 Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC > 19 percentLive load deflection limit:Allow. Δ ≤ L/360