Calculate the concentration of H+ of a solution that is 0.20…

Calculate the concentration of H+ of a solution that is 0.20 M in HF and 0.10 M in NaF Hint: HF is a weak acid (weak electrolyte) and NaF is an ionic compound (strong electrolyte); Consider the common ion F- when applying Ka for HF:    HF ↔ H+ +  F-   : The reaction is in equilibrium “↔” ; Ka ={ X } / NaF → Na+  + F-  :     

Two half-cells are shown below: Fe2+(aq)  +  2e-   ↔  Fe(s) …

Two half-cells are shown below: Fe2+(aq)  +  2e-   ↔  Fe(s)     Ecell = – 0.44 V Cu2+(aq)  +  2e-  ↔  Cu(s)    Ecell = +0.34 V Hint: The half-cell with the highest positive potential gets reduced. the other half-cell must get oxidized. Based on the cell voltage you received for question 21, what can you say about this cell?