A radiograph is made with a 36-inch source-to-image distance (SID) resulting in a receptor exposure of 0.01 milligray (mGy). What will the receptor exposure be if the SID is changed to 72 inches?

If an initial exposure is made using 400 mA, 1/10 sec, 40 mAs, 80 kVp, 50” SID, 12” OID, 8:1 grid ratio, 0.6 mm focal spot and 2.5 mm of filtration, with an 8 x 10 inch field size, and the technologist changes the SID to 60 inches for a second exposure without changing any other factors, what differences would you expect to see in the second exposure?1) Increased IR exposure2) Decreased IR exposure3) Increased contrast4) Decreased contrast5) Increased spatial resolution6) Decreased spatial resolution7) Increased distortion8) Decreased distortion

To calculate SOD:

If an x-ray beam has an intensity of 1.2 mGy at 60 inches, what is the intensity of the beam 40 inches?

An x-ray exposure is made using 96 kilovoltage peak (kVp) and 3 milliamperage (mA)s. What new technique will result in the greatest increase in receptor exposure?

A radiograph is acquired using a source-to-image distance (SID) of 40 inches. If the radiograph is repeated using the same exposure factors, but the SID increases to 60 inches, the receptor exposure will:

Considering radiographs produced with the following factors, which statement is true?Radiograph ARadiograph B500 mA500 mA0.02 sec0.08 sec36-inch SID72-inch SID

Which of the following formulas is used to determine the magnification factor?

An increase in kVp by 15 percent will cause an approximate ____ in the IR exposure.

kVp is the controlling factor for: