The prescriber orders ranitidine HCl (Zantac) 60 mg IV every…

The prescriber orders ranitidine HCl (Zantac) 60 mg IV every 6 hours for a patient weighing 68 lbs.                Dosage range: 5-10 mg/kg/day in 4 divided doses                The pharmacy has supplied ranitidine HCl (Zantac) 90 mg/6 mL   A)    What is the safe range/dose? _____________mg (tenth)  B)      Would you administer this medication and why?  _______________  

The prescriber has ordered acetaminophen (Tylenol) 500 mg, b…

The prescriber has ordered acetaminophen (Tylenol) 500 mg, by mouth every 6 hours for a temperature >101◦F. The patient weighs 65kg and has a temperature of 101.4◦F. Safe dosage range: 40–50 mg/kg/day in 4 divided doses. A. What is the safe dose range/dose? ________________mg (If rounding needed, round to the whole) B. Would the nurse administer this medication and why? _________________________  

For this question, answer it on your work paper. In the box…

For this question, answer it on your work paper. In the box below, type “complete” when finished. Make sure to show all of your work. Kp = 7.2 for the reaction:  Br2(g)  +  Cl2(g)   ⇄   2 BrCl(g) Calculate the value of Kp when the reaction changes to: 4 Br2(g)  +  4 Cl2(g) ⇄ 8 BrCl(g)      

For this question, answer it on your work paper. In the box…

For this question, answer it on your work paper. In the box below, type “complete” when finished. Make sure to show all of your work Consider the following reaction: 4 A(g) +  B(g)  ⇄   2 C(g) + 2 D(g) If 4.00 atm of compound A, and 4.00 atm of compound B are added to an empty container and allowed to react, what is Kp for the reaction if at equilibrium compounds C and D have a partial pressure of 1.20 atm?

For this question, answer it on your work paper. In the box…

For this question, answer it on your work paper. In the box below, type “complete” when finished. Make sure to show all of your work. Kp = 7.2 for the reaction:  Br2(g)  +  Cl2(g)   ⇄   2 BrCl(g) Calculate the value of Kp when the reaction changes to: 4 Br2(g)  +  4 Cl2(g) ⇄ 8 BrCl(g)