An Fe electrode in 0.020 M Fe²⁺ is connected to an Ag electr…

An Fe electrode in 0.020 M Fe²⁺ is connected to an Ag electrode in 0.0010 M Ag⁺. The cell potential at 25°C is _______  Standard reduction potentials: Fe2+ +     2e−→Fe(s)                      E∘=−0.44 V  Ag+   +    e−→Ag(s)                        E∘=+0.80 V Show your work on the scratch sheet

Which of the following is not a buffer system and why? A sol…

Which of the following is not a buffer system and why? A solution containing roughly equal concentrations of a) ammonia and ammonium         b) methyl amine and methyl ammonium  c) perchloric acid and perchlorate     d) hydrofluoric acid and fluoride Explain

Which of the following pairs of quantities become equal when…

Which of the following pairs of quantities become equal when the system is at equilibrium? A) The concentrations of reactants and productsB) The forward and reverse reaction ratesC) The reaction quotient Q and the initial concentrationsD) The total energy of the reactants and products Explain your choice.

You have been given an assertion statement and a reason. Sel…

You have been given an assertion statement and a reason. Select from A- D to locate the correct statement ? A) Both assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the assertion (A). B) Both Assertion (A) and reason (R) are true but Reason (R) is the not the correct explanation of the assertion (A). C) Assertion (A) is true, but Reason (R) is false. D) Assertion (A) is false, but Reason (R) is true.   Assertion (A): If Q = K Q=K the forward reaction will proceed until all reactants are converted into products. Reason (R): At equilibrium, the rates of the forward and reverse reactions are equal.

In a lab simulation, students investigated the decomposition…

In a lab simulation, students investigated the decomposition of hydrogen peroxide catalyzed by iodide ion 2H2O2(aq)       → 2(lH2O (l)     +      O2 (g)   They were given the following proposed reaction mechanism: Step 1: H2O2+I−→H2O+OI−\text{H}_2\text{O}_2 + \text{I}^- \rightarrow \text{H}_2\text{O} + \text{OI}^-  Step 2: H2O2+OI−→H2O+O2+I−\text{H}_2\text{O}_2 + \text{OI}^- \rightarrow \text{H}_2\text{O} + \text{O}_2 + \text{I}^- Student A made the following claim: “The iodide ion acts as a catalyst because it appears in the first step and disappears in the second.” Student B replied: “That can’t be right. The species that shows up in one step and is consumed in a later one without appearing in the overall reaction is actually the intermediate.” Based on their conversation, identify which species behaves as an intermediate in this mechanism.  Justify