Assume a, b, c, d and e are float variables, and the first four have values assigned. Which one of the following is the correct way to first add a and b, then divide by the difference between c and d, and assign the result to variable e?

A projectile is launched from ground level at an angle of 50.0° above horizontal with a speed of 30.0 m/s. If the projectile is moving over level ground, how long is it in the air before it again contacts the ground?

FIGURE 2-9 f4g1q30g1.jpg Refer to Fig. 2-9. If you start from the Bakery, travel to the Art Gallery, and then to the Cafe, in 1.0 hour, what is your average speed?

FIGURE 2-9 f4g1q24g1.jpg Refer to Fig. 2-9. If you start from the Bakery, travel to the Cafe, and then to the Art Gallery, what is the magnitude of your displacement?

prob 22 pic.png Determine the direction’ measured counter-clockwise from the positive x-direction’ of the acceleration for m = 2.0 kg, F1 = 32.0 N, F2 = 18.0 N, F3 = 22.0 N, θ1 = 37.00, and θ2 = 25.00.

prob 17 pic.png Determine the acceleration of the object up the incline if the coefficient of kinetic friction between the object and the surface is 0.40 for m = 6.0 kg, F = 83.0 N,  and q = 26.00.

Consider the relation Sells (bar, beer, price) and the following view that has been created to list beers sold in specific bars:   CREATE VIEW BeersView AS SELECT beer, price FROM Sells WHERE beer IN (SELECT beer FROM Sells WHERE bar = ‘Joe”s Bar’);   Why might this view not allow updates or inserts?      

Suppose we have Sells (bar, beer, price) relation and a view is created to show all beers priced below $5:   CREATE VIEW AffordableBeers AS SELECT beer, price FROM Sells WHERE price < 5; A user attempts to insert the following record through the view:   INSERT INTO AffordableBeers (beer, price) VALUES ('Corona', 6.00); What will happen in this case?    

Can a materialized view improve performance for queries that are run multiple times with the same data?

Suppose we have two relations Sells (bar, beer, price) Beers (name, manf) And the Sells table includes a foreign key constraint on beer, referencing the Beers table. The foreign key is defined as: FOREIGN KEY (beer) REFERENCES Beers (name) ON DELETE SET NULL ON UPDATE CASCADE; What happens when a record in the Sells table with beer =’Budweiser’ is updated to beer =’Bud Light’? Assuming we have a record in the Beers relation with name =’Budweiser’