Radiometric dating is based on the ______ of certain isotopes, like C-14 or K-40.

In the ____________  _______________ part of the population leaves or is separated by a barrier, so that alleles in this new population are dictated by chance alone. _______ _______

____________________ is when two different species, like a bat and a flower, evolve in response to each other. _______

In order for technological development to occur, a practical use for the technology must first be clearly identified. 

A procedure is underdetermined if, for certain inputs, its specification allows more than one possible result.

Consider the following code, and suppose the main method in Sub is executed. public class Super { private String y; public Super () { stut();} public void stut() { if (y == null) {y = “cat”;} else {y = y + y;}} } public class Sub extends Super { private String x; public Sub (String s) { x = s;} @Override public void stut() { x = x + x; } public static void main(String[] args) { Super s = new Sub(“dog”); } } Is this true or false: the stut() method in Super is invoked

Subclasses/inheritance can have negative consequences because  (select all correct answer(s) and no incorrect answer(s) to get credit)

If a method is declared with default access, it can only be overridden by methods in the same package

What is the output of the code below?   class A {                public int x;                public A(int x) { this.x = x; }                public String toString() { return “x = ” + x; } }   class Super {   public A a;   public Super() {                System.out.println(“Super()”);                foo();   }   public Super (A a) {                System.out.println(“Super(A a)”);                this.a = a;                foo();   }   public void foo() {                System.out.println(“Super.foo()”);                System.out.println(a);   } }   public class Sub extends Super {   public A a;   public Sub() {                System.out.println(“Sub()”);                foo();   }   public Sub (A a) {                System.out.println(“Sub(A a)”);                this.a = a;                foo();   }   @Override public void foo() {                    System.out.println(“Sub.foo()”);                System.out.println(a);   } } public static void main(String[] args) {      new Super(new A(2)); }  

What are some differences between interfaces and abstract classes in Java (select all correct answer(s) and no incorrect answer(s) to get credit)?