@X@user.full_name@X@ @GMU: A compound contains only magnesium and fluorine. A sample weighing 5.56 g of this compound contained 2.17 g of magnesium. How many grams of fluorine would there be in another sample of this compound containing 4.16 g of magnesium?

@X@user.full_name@X@ @GMU: What is the total concentration of ions in a solution consisting of 0.4777 M NaOH?

@X@user.full_name@X@ @GMU: What is the free energy change for the reaction below, if the reaction quotient, Q, at 25.0oC is equal to 8.98e-7?3C2H2(g) → C6H6(g) ΔGo = -498.180 kJ.

@X@user.full_name@X@ @GMU: Using bond energies from the table below, estimate ΔH for the reaction below.CH3I(g) + HI(g) → CH4(g) + I2(g) Bond Energies, kJ/mol Single Bonds   H C N O S F Cl Br I H 432                 C 411 346               N 386 305 167             O 459 358 201 142           S 363 272 — — 286         F 565 485 283 190 284 155       Cl 428 327 313 218 255 249 240     Br 362 285 243 201 217 249 216 190   I 295 213 — 201 — 278 208 175 149   Multiple Bonds C=C 602 C=N 615 C=O 799 CºC 835 CºN 887 CºO 1072 N=N 418 N=O 607 S=O (in SO2) 532 NºN 942 O2 494 S=O (in SO3) 469

@X@user.full_name@X@ @GMU: What is the empirical formula of a compound if its percent composition is 65.69 % C and 15.16 % H? The compound contains only C, H and N.

@X@user.full_name@X@ @GMU: What is the free energy change for the reaction below, if the reaction quotient, Q, at 25.0oC is equal to 5.91e-8?4C2H2(g) + 5 H2(g) → C8H18(g) ΔGo = -819.870 kJ.

@X@user.full_name@X@ @GMU: What is the correct name for Ni3N2?

The complete combustion of propanone, CH3COCH3, yields carbon dioxide and water as products (see reaction below). __CH3COCH3 + __O2 ↔ __CO2 + __H2O The ratio of the number of molecules of O2 required to molecules of propanone is

@X@user.full_name@X@ @GMU: What is the standard cell voltage at 25.0oC for the reverse of the reaction below?Hg2+(aq) + 2MnO42-(aq) → Hg(l) + 2MnO4-(aq) K = 6.44e9

@X@user.full_name@X@ @GMU: What is the total concentration of ions in a solution consisting of 0.4847 M NaBr?