A patient is admitted with sickle cell crisis. The patient h…

A patient is admitted with sickle cell crisis. The patient has pain with a pain of 8 out of 10 on a pain scale and with the following vital signs: HR elevated at 115, BP is good at 120/82, RR is good at 18, oxygen saturation is low at 83%, and elevated temperature of 101.2’F. Based on these vitals, what will the nurse do (implement) first?

Use this table for the following questions.  Assume you don’…

Use this table for the following questions.  Assume you don’t have the lab manual table to answer the questions.  Antibiotic Patient A (Zone of Inhibition in mm) Patient B (Zone of Inhibition in mm) Erythromycin 10 mm 25 mm Tetracycline 20 mm 2 mm Ampicillin 0 mm 1 mm Penicillin 30 mm 16 mm a. Based on the zones of inhibition, which antibiotic would you use to treat Patient A? b. Based on the zones of inhibition, which antibiotic would you use to treat Patient B?

Q45. A Golden retriever (photo ‘A’) has cutaneous histiocyto…

Q45. A Golden retriever (photo ‘A’) has cutaneous histiocytosis, an inflammatory Lymphohistiocytic proliferative disorder that primarily involves skin and subcutis. Lesions may disappear spontaneously or regress and appear at new sites simultaneously. A biopsy of the skin (see photomicrograph ‘B’) reveals cells that are on IHC and express CD1, CD11c, MHC class II, CD4, and CD90. On transmission EM (see photomicrograph ‘C’), the tumor cells contain Birbeck granules comprised of antigen-bound Langerin (Langerin is a c-type lectin). Which of the following types of immune cells is most likely responsible for the inflammatory infiltrate in this dog? 

You are mapping a gene associated with a Mendelian disease,…

You are mapping a gene associated with a Mendelian disease, and you observe that every member of a large family afflicted with the disease shares the same RFLP pattern at a position on Chr. 11. Every member who doesn’t have the disease has a different RFLP pattern at that same position on Chr. 11. What is the next step?

A genome wide association study of 270,000 SNPs identifies a…

A genome wide association study of 270,000 SNPs identifies a SNP of interest on Chr 9. In a population of individuals with inflammatory bowel disease, 82% of the people have a Thymine and 18% have a Guanine. In the control population, 27% of the people have an Thymine and 73% have a Guanine. The Thymine SNP on Chr 9 has an OR of 2.3. The difference in the SNP frequencies between the case and control population has a p value < 5 x 10-12.  In one sentence or in just a few words, what can researchers conclude about this result?