The data below displays heights (in inches) of a random samp…

The data below displays heights (in inches) of a random sample of students and their parent of the same sex. Student (s) 70 65 68 63 72 71 Parent (p) 65 67 64 63 70 66 Difference (s-p) 5 -2 4 0 2 5 The mean for the difference between student and parent heights is   = 2.33 and the sample standard deviation for the difference between student and parent heights is sD = 2.88.   We can assume the distribution of the differences is Normal. The p-value for this hypothesis test is 0.0218.  At a 0.05 significance level, what conclusion can you make?

Use this scenario to answer the next two questions.  Male p…

Use this scenario to answer the next two questions.  Male players at the high school, college, and professional ranks use regulation basketballs that weigh on average 22 ounces with a standard deviation of 1 ounce.  Assume that the weights of the basketballs are Normally distributed.  If a regulation basketball is randomly selected, what is the probability that it will weigh greater than 23.5 ounces?  Choose the best answer.

The director of employee benefits at a midsize company wants…

The director of employee benefits at a midsize company wants to determine the amount spent on health care by the typical hourly worker in the company.  A random sample of 21 workers is selected and the amount they spent on their families’ health care needs during the past year was collected and used to create the graphics below.  The director wishes to determine if the average hourly employee in the company spent less than $400 per year on his or her family’s health care needs.  Would conducting a hypothesis test using the t-distribution be appropriate in this situation?