A 44-year-old presents to the clinic for a wellness examination. The nurse practitioner notes that the patient is obese, smokes, is under stress at work and is on oral contraceptives. The nurse practitioner recognizes these as risk factors for
Example The average length of a maternity stay in a U.S. hos…
Example The average length of a maternity stay in a U.S. hospital is said to be 2.4 days with a standard deviation of 0.9 days. We randomly survey 55 women who recently bore children in a U.S. hospital. What is the probability that their average stay is no more than 2.5 days. n = = = = = Round to 4 decimal places.
The life of Sunshine CD players is normally distributed with…
The life of Sunshine CD players is normally distributed with a mean of 4.1 years and a standard deviation of 1.3 years. We are interested in the length of time a CD player lasts. Find the probability that a Sunshine CD player will last longer than years. Round to 4 decimal places.
Link to Examples Using StatCrunch Link to Examples Using TI…
Link to Examples Using StatCrunch Link to Examples Using TI 83/84 Calculator X∼N(295, 43). Find the probability that x
Example The average length of a maternity stay in a U.S. hos…
Example The average length of a maternity stay in a U.S. hospital is said to be 2.4 days with a standard deviation of 0.9 days. We randomly survey 60 women who recently bore children in a U.S. hospital. What is the probability that their average stay is at least 2.5 days n = = = = = Round to 4 decimal places.
Link to Examples Using StatCrunch Link to Examples Using TI…
Link to Examples Using StatCrunch Link to Examples Using TI 83/84 Calculator X∼N(56.8, 2.1). Find the probability that 60
Example The average length of a maternity stay in a U.S. hos…
Example The average length of a maternity stay in a U.S. hospital is said to be 2.4 days with a standard deviation of 0.9 days. We randomly survey 35 women who recently bore children in a U.S. hospital. What is the probability that their average stay is between 1 and 2 days, inclusive. n = = = = = Round to 4 decimal places.
Link to Examples Using StatCrunch Link to Examples Using TI…
Link to Examples Using StatCrunch Link to Examples Using TI 83/84 Calculator X∼N(56.8, 2.1). Find the probability that 60
Heights of adult women are approximately normally distribute…
Heights of adult women are approximately normally distributed with a mean of 64.5 inches and a standard deviation of 2.5 inches. Find the probability that a randomly select adult woman has a height between 62 and 66 inches. Round to 4 decimal places. Find the 25th percentile. (Find the height with an area of 0.25 to its left.) Round to 1 decimal place.
Heights of adult women are approximately normally distribute…
Heights of adult women are approximately normally distributed with a mean of 64.5 inches and a standard deviation of 2.5 inches. Find the probability that a randomly select adult woman has a height between 65 and 71 inches. Round to 4 decimal places. Find the 85th percentile. (Find the height with an area of 0.85 to its left.) Round to 1 decimal place.