Example The average length of a maternity stay in a U.S. hospital is said to be 2.4 days with a standard deviation of 0.9 days. We randomly survey 60 women who recently bore children in a U.S. hospital. What is the probability that their average stay is at least 2.5 days n = = = = = Round to 4 decimal places.
Example The average length of a maternity stay in a U.S. hos…
Example The average length of a maternity stay in a U.S. hospital is said to be 2.4 days with a standard deviation of 0.9 days. We randomly survey 35 women who recently bore children in a U.S. hospital. What is the probability that their average stay is between 1 and 2 days, inclusive. n = = = = = Round to 4 decimal places.
Example The average length of a maternity stay in a U.S. hos…
Example The average length of a maternity stay in a U.S. hospital is said to be 2.4 days with a standard deviation of 0.9 days. We randomly survey 80 women who recently bore children in a U.S. hospital. What is the probability that their average stay is between 2 and 2.5 days, inclusive. n = = = = = Round to 4 decimal places.
Heights of adult women are approximately normally distribute…
Heights of adult women are approximately normally distributed with a mean of 64.5 inches and a standard deviation of 2.5 inches. Find the probability that a randomly select adult woman has a height between 65 and 71 inches. Round to 4 decimal places. Find the 85th percentile. (Find the height with an area of 0.85 to its left.) Round to 1 decimal place.
Heights of adult women are approximately normally distribute…
Heights of adult women are approximately normally distributed with a mean of 64.5 inches and a standard deviation of 2.5 inches. Find the probability that a randomly select adult woman has a height between 62 and 66 inches. Round to 4 decimal places. Find the 25th percentile. (Find the height with an area of 0.25 to its left.) Round to 1 decimal place.
Example The average length of a maternity stay in a U.S. hos…
Example The average length of a maternity stay in a U.S. hospital is said to be 2.4 days with a standard deviation of 0.9 days. We randomly survey 80 women who recently bore children in a U.S. hospital. What is the probability that their average stay is between 2 and 2.5 days, inclusive. n = = = = = Round to 4 decimal places.
Link to Examples Using StatCrunch Link to Examples Using TI…
Link to Examples Using StatCrunch Link to Examples Using TI 83/84 Calculator X∼N(130, 24). Find the probability that x>100. Round to 4 decimal places. mean = standard deviation = probability =
Heights of adult women are approximately normally distribute…
Heights of adult women are approximately normally distributed with a mean of 64.5 inches and a standard deviation of 2.5 inches. Find the probability that a randomly select adult woman has a height between 68 and 72 inches. Round to 4 decimal places. Find the 70th percentile. (Find the height with an area of 0.70 to its left.) Round to 1 decimal place.
IQ scores are normally distributed with a mean of 100 and a…
IQ scores are normally distributed with a mean of 100 and a standard deviation of 15. Calculate the z-score for an IQ score of . Round to 1 decimal places. Formula:
Did you understand the Academic Honesty Policy for this cour…
Did you understand the Academic Honesty Policy for this course?