Determine the ASD adjusted modulus of elasticity, E’, for the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:PD = 600 lbPLr = 1,760 lbLoad combination:D + LrSpan:L = 10 ftMember size:4 x 14Stress grade and species:No. 2 Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC > 19 percentLive load deflection limit:Allow. Δ ≤ L/360

Determine the tension Ft reference design value for 28F-2.1E SP softwood glulams.

What is the moment of inertia, Ixx, about the X-X axis for 5-1/2 in. x 16 in. Western Species glulams?

A 2 x 10 rafter frames into a 2 x 8 stud wall. The load is a combination of PD = 100 lb and PS = 570 lb. Consider the D + S load combination. Determine the ASD actual bearing stress fc⊥ in the top plate of the wall.

Determine the ASD adjusted modulus of elasticity, E’, for the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:PD = 480 lbPLr = 2,080 lbLoad combination:D + LrSpan:L = 12 ftMember size:4 x 6Stress grade and species:No. 1 & Better Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC > 19 percentLive load deflection limit:Allow. Δ ≤ L/360

A wood member is loaded as shown. Using ASD, determine the adjusted bending strength, Fb’. Assume normal temperatures, no incising, and that all loads act in the directions shown. Ignore the weight of the member.Load:PD = 3,000 lbPL = 0 lbPLr = 0 lbPS = 0 lbPR = 0 lbPW = 7,500 lbPE = 7,500 lbQD = 3,000 lbQL = 3,000 lbQLr = 5,000 lbQS = 500 lbQR = 500 lbQW = 0 lbQE = 0 lbSpan:L = 11 ft Member size:4 x 6 Stress grade and species:No. 1 & Better Douglas Fir-Larch Unbraced length:lu = 0 ft Moisture content:MC > 19 percent 

Determine the ASD adjusted minimum modulus of elasticity, Emin’, for the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:PD = 520 lbPLr = 1,600 lbLoad combination:D + LrSpan:L = 12 ftMember size:4 x 12Stress grade and species:No. 2 Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC > 19 percentLive load deflection limit:Allow. Δ ≤ L/360

Determine the ASD adjusted design compression strength parallel to grain, Fc’, for the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:wD = 200 lb/ftwLr = 330 lb/ftLoad combination:D + LrSpan:L = 6 ftMember size:4 x 10Stress grade and species:Select Structural Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC < 19 percentLive load deflection limit:Allow. Δ ≤ L/360

Determine the maximum actual bending stress in the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:PD = 560 lbPLr = 1,760 lbLoad combination:D + LrSpan:L = 13 ftMember size:4 x 10Stress grade and species:No. 1 & Better Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC < 19 percentLive load deflection limit:Allow. Δ ≤ L/360

A 2 x 10 rafter frames into a 3 x 4 stud wall. The load is a combination of PD = 140 lb and PS = 450 lb. Consider the D + S load combination. Determine the ASD actual bearing stress fc⊥ in the top plate of the wall.