During a fluoroscopy procedure, the x-ray technologist stands at 5 meters from the x-ray tube for 1 hour and acquires an equivalent dose of 0.1 mSv. If the technologist had stood at a distance of 1 meter, what would their dose have been?

The inverse square law defines the relationship between distance and:

If an optimal radiograph is acquired at 72 inches with an air kerma of 4 mGy, what will the air kerma be if the distance is reduced to 40 inches?

Scattered radiation that hits the image receptor produces:

A satisfactory x-ray of the wrist is produced using a technique of 300 milliamperes (mA), 15 milliseconds, 50 kilovoltage peak (kVp), and a source-to-image distance (SID) of 40 inches. How should the mA be changed if the exposure time is decreased to 10 milliseconds?

All factors remaining constant, which of the following set of exposure conditions would yield an image with the GREATEST radiographic IR exposure?

Contrast increases with all of the following EXCEPT

If the same exposure factors are used on four different radiographs and all that is changed is the SID, which radiograph would have the greatest IR exposure? The one taken at a:

When changing your SID from 72” to 50”

Which one of these tells the radiographer what new mAs to use when the SID changes to maintain IR exposure?