(06.04 MC) If w = 10 units, x = 5 units, and y = 6 units, what is the surface area of the figure? Round your answer to the nearest tenth.

(06.01 MC) The cross-sectional areas of a right triangular prism and a right cylinder are congruent. The right triangular prism has a height of 6 units, and the right cylinder has a height of 4 units. Which conclusion can be made from the given information?

The English phrase “taking off” will always have the same sign in ASL regardless of the situation.

What does the prefix “lexical” signify?

(06.04 MC) One link in a chain was made from a cylinder that has a radius of 2 cm and a height of 20 cm. How much plastic coating would be needed to coat the surface of the chain link? Use 3.14 for π.

(06.04 MC) One link in a chain was made from a cylinder that has a radius of 2.5 cm and a height of 22 cm. How much plastic coating would be needed to coat the surface of the chain link? Use 3.14 for π.

(06.03 LC) Amelia is calculating the density of soccer balls in a bag. She knows the number of balls in the bag and the volume of the bag. Which of the following formulas can be used to calculate the density of balls in the bag?

(06.01 MC) A square prism and a cylinder have the same height. The area of the cross-section of the square prism is 157 square units, and the area of the cross-section of the cylinder is 50π square units. Based on this information, which argument can be made?

(06.01 MC) A square prism and a cylinder have the same height. The area of the cross-section of the square prism is 314 square units, and the area of the cross-section of the cylinder is 50π square units. Based on this information, which argument can be made?

(06.01 MC) Jude says that the volume of a square pyramid with base edges of 9.7 in and a height of 9 in is equal to the volume of a cylinder with a radius of 5.47 in and a height of 3 in. Jude rounded his answers to the nearest whole number. Examine Jude’s calculations. Is he correct? Volume of Square Pyramid Volume of Cylinder V = B(h) V = πr2h V = (94.09)(9) V = π(5.472)(3) V = (846.81) V = π(29.9209)(3) V = 282 in3 V = π(89.7627)   V ≈ 282 in3