The weak acid, hydrocyanic acid (HCN) is dissolved in water…

Questions

The weаk аcid, hydrоcyаnic acid (HCN) is dissоlved in water tо make a 0.15 M solution. Hydrocyanic acid has a Ka = 4 x 10-10. Answer the below questions about this solution when it has reached equilibrium.  PART A: Which of the below options correctly represents the acid dissociation constant expression for the dissociation/ionization reaction of HCN in water? Type your letter answer in the box below in all lowercase. If more than one option applies, type all letters that are correct with no spaces between them. For example: cde [blank1]  PART B: Calculate the concentrations of all reactants and products at equilibrium. Round your answers to one decimal place AND use the below format for any scientific notation values where the first blank box is for the number and the second box is for the exponent. Example: for 1.5 X 10-4 the 1.5 would go in the first blank box below and the -4 exponent would go in the second blank box below with no spaces.   HCN                  = [blank2]  CN-                    = [blank3] X 10^ [blank4] H3O+                 = [blank5] X 10^ [blank6]   PART C: What is the pH of this solution. Round your answer to 1 decimal place pH = [blank7]    PART D: What is the pOH of this solution. Round your answer to 1 decimal place. pOH = [blank8]    PART E: What is the hydroxide (OH-) concentration of this solution? Round your answer to no decimal places AND use the below format for any scientific notation values where the first blank box is for the number and the second box is for the exponent. Example: for 1 X 10-4 the 1 would go in the first blank box below and the -4 exponent would go in the second blank box below with no spaces. OH-          = [blank9] X 10^ [blank10]    PART F: Is this solution acidic or basic? Type in all lowercase either acidic or basic below  [blank11]

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