8.00 ml of 0.50 M HCl reacts with 8.00 mL of 0.50 M Ba(OH)2…
8.00 ml of 0.50 M HCl reacts with 8.00 mL of 0.50 M Ba(OH)2 in a stoichiometry study using the methods of continuous variations. The stoichiometry of the system was shown by the following balanced equation: Ca(OH)2(aq) + 2HCl(aq) → CaCl2(aq) + 2H2O(l) On the basis of the limiting reagent, calculate the theoretical number of moles of product (BaBr2) that should have been formed.