The dissolution of PbN3(s) in water has the following reacti…
The dissolution of PbN3(s) in water has the following reaction and equilibrium constant: PbS(s) ⇌ Pb2+(aq) + N3−(aq), K = 1×10−9 Given that HN3 has Ka = 1×10−5, what is the equilibrium constant for the dissolution in PbN3(s) in an acidic solution: PbS(s) + 2 H3O+(aq) ⇌ Pb2+(aq) + 2 HN3(aq) + 2 H2O(l)