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A proton having a speed of 3.0 × 10^6 m/s in a direction per…

A proton having a speed of 3.0 × 10^6 m/s in a direction perpendicular to a uniform magnetic field moves in a circle of radius 0.20 m within the field.  What is the magnitude of the magnetic field? (e = 1.60 × 10^-19 C, mproton = 1.67 × 10^-27 kg)

A proton having a speed of 3.0 × 10^6 m/s in a direction per…

Posted on: June 3, 2025 Last updated on: June 3, 2025 Written by: Anonymous Categorized in: Uncategorized
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