Charles Law: A flask with an initial volume of dry air equal…
Charles Law: A flask with an initial volume of dry air equal to 200.0 ml was heated to boiling water temperature. The hot flask was closed, transferred into a water bath with a temperature of 23.0 °C, and then reopened underwater and the height of the flask was adjusted so that the level of the water in the flask was same as the level of the water in the sink, and under these conditions the flask was closed. The volume of water drawn into the flask was 25.0 ml. Let 0 oC = 273.2 K. A. (0.5 pts) What is the experimentally determined volume of the air in the flask at 23.0 oC? Round to 1 decimal place. = mL B. (2 pts) What is the calculated value for this volume using Charles’ Law? Round answer to 1 decimal place. = mL C. (0.5 pts) What is the % error of the experiment with respect to that predicted from Charles’ Law? Round answer to 1 decimal place. Remember: Percentage error = x 100% = % D. (2 pts) Considering the pressure change, recalculate the volume using 760.0 mmHg for atmospheric pressure and 21.068 mmHg for the vapor pressure of water at 23.0 °. Round answer to 1 decimal place. Remember: (P1V1)/T1 = (P2V2)/T2 = mL E. (1 pts) What is % error of the experiment (a) with respect to the volume in calculated in (d)? Round your answer to two decimal places. = %