Info for Questions 22-26 This diagram shows how the carbon s…
Info for Questions 22-26 This diagram shows how the carbon skeleton of the amino acid Leu is broken down to Acetyl CoA and to the 4-carbon atom compound acetoacetate, which corresponds to compound 6 on the diagram. Identify the cofactor or parallel reaction for each question. Some answer options may be used more than once, and some answer options will not be used. Some questions have more than one acceptable answer that will receive credit. Use the image below for questions 22-26. Answer Options aldolase aconitase alpha-ketoglutarate dehydrogenase complex enolase fumarase hexokinase pyruvate dehydrogenase complex pyruvate kinase succinyl CoA synthetase succinate dehydrogenase Image Description A stepwise biochemical pathway showing the conversion of a substrate into Acetyl CoA through six steps. The pathway begins with leucine. In Step 1, leucine is deaminated, with the amine being replaced by a ketone. In Step 2, the carboxylic acid is removed and replaced by SCoA. In Step 3, a single bond between a CH and a CH2 is replaced by a double bond, both carbons losing one hydrogen in the process. In Step 4, one of the methylene groups on the terminal end of the leucine’s R chain has a carboxylic acid attached to it. In Step 5, the carbon-carbon double bond created in Step 3 is removed, with the CH being converted back into CH2 and the C getting an alcohol attached to it. In Step 6, Acetyl CoA is removed from the structure.