A genome wide association study of 270,000 SNPs identifies a…
A genome wide association study of 270,000 SNPs identifies a SNP of interest on Chr 9. In a population of individuals with inflammatory bowel disease, 82% of the people have a Thymine and 18% have a Guanine. In the control population, 27% of the people have an Thymine and 73% have a Guanine. The Thymine SNP on Chr 9 has an OR of 2.3. The difference in the SNP frequencies between the case and control population has a p value < 5 x 10-12. In one sentence or in just a few words, what can researchers conclude about this result?