According to the following reaction, what mass of PbCl2 can…
According to the following reaction, what mass of PbCl2 can form from 235 mL of 0.210 M KCl solution? Assume that there is excess Pb(NO3)2. KCl = 74.548 g/mol; Pb(NO3)2 = 331.208 g/mol; PbCl2 = 278.1 g/mol; KNO3 = 101.102 g/mol 2 KCl(aq) + Pb(NO3)2(aq) → PbCl2(s) + 2 KNO3(aq)
According to the following reaction, what mass of PbCl2 can…
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Accоrding tо the fоllowing reаction, whаt mаss of PbCl2 can form from 235 mL of 0.210 M KCl solution? Assume that there is excess Pb(NO3)2. KCl = 74.548 g/mol; Pb(NO3)2 = 331.208 g/mol; PbCl2 = 278.1 g/mol; KNO3 = 101.102 g/mol 2 KCl(aq) + Pb(NO3)2(aq) → PbCl2(s) + 2 KNO3(aq)