A light-bulb manufacturer advertises that the average life f…

A light-bulb manufacturer advertises that the average life for its light bulbs is 900 hours. A random sample of 15 of its light bulbs resulted in the following lives in hours.995       590       510     539         739        917       571         555916       728       664      693        708        887       849 Assume the sample comes from a normal distributed population. At the 0.10 significance level, test the claim that the sample is from a population with a mean life of 900 hours. Make sure to provide the appropriate symbol, formula and round off rule for each step (14pts) Round the sample mean and the sample standard deviation to one decimal place. Perform the following steps:  (3pts) Step 1: Requirements (2pts) Step 2: H 0                       H 1 (3pts) Step 3: Test statistic (round to 3 decimal places) (3pts) Step 4: p-value (round to 3 decimal places)          (2pts) Step 5: p- value method (1pt) Step 6: Conclusion  

Use the given degree of confidence and sample data to constr…

Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ. Assume that the population has a normal distribution.The football coach randomly selected twelve players and timed how long each player took to perform a certain drill. The times (in minutes) were:7.0     10.8    9.5    8.0    11.5    7.5     6.4    11.3    10.2    12.6     8.5    6.8Determine a 96% confidence interval for the mean time for all players. Make sure to provide sufficient work for the prompts below. (5 pts)  (1pt) Calculator command: (2pts) Information input:  (1pt) CI (round to 2 decimal places)  (1pt) Interpretation:

A cereal company claims that the mean weight of the cereal i…

A cereal company claims that the mean weight of the cereal in its packets is 14 oz. The weights (in ounces) for the cereal in a random sample of 8 of its cereal packets are listed below. 14.6       13.8        14.1     13.7       14.0      14.4      13.6       14.2   Assume the sample comes from a normal distribution population. Test the claim at the 0.01 significance level. (14pts) Round the sample mean and the sample standard deviation to 2 decimal places. Perform the following steps:  (3pts) Step 1: Requirements (2pts) Step 2:                 (3pts) Step 3: Test statistic (round to 3 decimals) (3pts) Step 4: p- value (round to 4 decimals) (2pts) Step 5: P- value Method  (1pt) Step 6: Conclusion  

Use the given degree of confidence and sample data to constr…

Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ. Assume that the population has a normal distribution.A sociologist develops a test to measure attitudes towards public transportation, and 27 randomly selected subjects are given the test. Their mean score is 76.2 and their standard deviation is 21.4. Construct the 94% confidence interval for the mean score of all such subjects using a calculator command. Make sure to include correct symbol, formula and round off rule for each step. (12pts)  (2pts) Point estimate (sample mean)  (3pts) Critical value ( Round to 3 decimal places)(3pts) Margin of Error (Round to 1 decimal place)(3pts) CI (Round to 1 decimal place)(1pt) Interpretation:

Find the indicated probability. (4pts)A tennis player makes…

Find the indicated probability. (4pts)A tennis player makes a successful first serve 51% of the time. If she serves 9 times, what is the probability that she gets exactly 5 first serves in? Assume that each serve is independent of the others. Make sure to first define variable X, then calculate the probability Define variabale X=

A marketing survey involves product recognition in New York…

A marketing survey involves product recognition in New York and California. Of 558 New Yorkers surveyed, 193 knew the product while 196 out of 614 Californians knew the product. At the 0.05 significance level, test the claim that the recognition rates are the same in both states.  Show detailed work for the steps below. (14pts) 1) (2pts) Ho:                 H1:  2) (3pts) Requirements:  3) (3pts) Test statistic (round to 3 decimal places):  4) (3pts) P-value (round to 4 decimal places):  5) (2pts) P-value method:  6) (1pt) Conclusion: 

Provide an appropriate response.In a survey, 26 voters were…

Provide an appropriate response.In a survey, 26 voters were asked their ages. The results are shown below. 43  56  28  63  67  66  52   48  37   51   40    60   62 66  45  21  35  49  32  53   61   53   69   31   48   59a) Construct a frequency distribution to represent the data (with 5 classes beginning with a lower class limit of 20 and a class width of 10). Also state all the class midpoints and class boundaries (9pts) b) Construct a frequency histogram for the data. Determine the distribution shape of the data. Make sure to label all the axes (7pts) c) Construct a cumulative frequency distribution for the data. Then construct an ogive graph for the data. Make sure to label all the axes (10pts) d) Construct a frequency polygon for the data. Make sure to label all the axes (5pts) g) Construct a stem and leaf plot for the data (5pts) h) List the 5-number summary. Make sure to include the calculator command (4pts) i) Construct a box-plot for the data (5pts)