Consider the voltaic cell diagram:  Al (s) | Al3⁺(aq) || Fe2…

Consider the voltaic cell diagram:  Al (s) | Al3⁺(aq) || Fe2⁺ (aq) | Fe (s) What is the standard cell potential, E°cell, (in V) for this voltaic cell? Hint: Refer to the table of standard reduction potentials provided. Half Reaction E° red (V) Ag+ (aq)  + e–  →  Ag (s)  +0.80 Fe3+ (aq)  +   e–  → Fe2+ (aq)   +0.77 Cu2+ (aq)  + 2 e–  → Cu (s)    +0.34 Sn4+ (aq) + 2 e–  → Sn2+ (aq)   +0.15 2H+ (aq) + 2 e–  →  H2 (g)  0.00 Pb2+ (aq) + 2 e –  → Pb (s)  –0.13 Sn2+ (aq)  +  2 e–  → Sn (s)  –0.14 Ni2+ (aq) + 2 e –  → Ni (s)   –0.28 Cd2+ (aq) + 2 e –  → Cd (s)   –0.40 Fe2+ (aq) + 2 e –  → Fe (s) –0.44 Cr3+ (aq) + 3 e– →  Cr (s)      –0.74 Zn2+ (aq) + 2 e –  → Zn (s)  –0.76 Al3+ (aq) + 3 e– →  Al (s) –1.66  

Given the following reduction potentials:                  …

Given the following reduction potentials:                                                               Eored Cr3+(aq)  + 3e- →  Cr(s)                      –0.74 V Fe3+(aq)  +  e- →  Fe2+(aq)                 +0.77 V Calculate the equilibrium constant, K, for the following reaction.               Cr(s)    + 3    Fe3+(aq)   →   Cr3+(aq) + 3 Fe2+(aq) Hint:  Remember that a voltaic cell runs on a spontaneous redox reaction.   Hint: Make sure to determine the total moles of electrons transferred for the cell.  

There are two sequences X= and Y=.  You need to use the dyna…

There are two sequences X= and Y=.  You need to use the dynamic programming algorithm taught in class to compute a longest common subsequence (LCS) of X and Y. You need to compute the values of c and b. For the value of b, N denotes an up arrow, W denotes a left arrow, NW denotes an arrow to the upper-left. The value of b is

This question is concerned with hashing with open addressing…

This question is concerned with hashing with open addressing, where the table size is 13 (indexed from 0 to 2) and the (linear) probing sequence is defined by h'(k) = k mod 13 and h(k, i) = (h'(k) + i) mod 13. Assume that the content of the hash table T is as follows: T = 13 T = 14 T = DELETED T = 15 T = NIL T = 5 T = DELETED T = 19 T = NIL T = 9 T = 23 T = 24 T = 25   How many cells does Hash-Delete(T, 19) probe? Please note that this question does not ask which cell is probed? It asks about HOW MANY.