Answer the following question. Show the answer on the screen…

Answer the following question. Show the answer on the screen provided. After uploading your exam, take the picture of your work and upload it to Exam 4 Solutions, Extra Credit, and Partial Credit assignment. Your work must reflect the answer provided here. NO CREDIT will be awarded for the answer without work shown. 15.3 g of KClO3 decomposes according to the following balanced equation. Use the stoichiometry and gas laws to determine the volume of O2 formed at 1 atm and 500K. The molar mass for KClO3 is 122.55 g/mol.                 2 KClO3(s)  →  2 KCl(s) + 3 O2(g)

Answer the following question. Show the answer on the screen…

Answer the following question. Show the answer on the screen provided. After uploading your exam, take the picture of your work and upload it to Exam 4 Solutions, Extra Credit, and Partial Credit assignment. Your work must reflect the answer provided here. NO CREDIT will be awarded for the answer without work shown. Standard Enthalpies of Formation, in kJ/mol ΔHof     ΔHof NO(g)       +90.25          NO2(g)      +33.2        NH3(g)     -45.9     N2O(g)        81.6   H2O(l)        -285.8         H2O(g)         -241.8 Use the properties of enthalpy as a state function (version of Hess’s law) and  data above to calculate the enthalpy change for the reaction (Hint: Do not forget about the coefficients):                                          6 NO2(g)  +  8 NH3(g)  =>  7 N2(g)  +  12 H2O(g)                      ΔH = ?  

Use the special form of Hess’s law and given ∆H°f of the rea…

Use the special form of Hess’s law and given ∆H°f of the reactants and products to calculate the heat for the reaction(∆H°rxn) of methane with oxygen :  CH4 (g)  +  2O2(g)   →  CO2(g) +2H2O(l) ∆H°f, methane(g) = -74.60 kJ/mol ∆H°f, water(l) = -285.8 kJ/mol ∆H°f, carbon dioxide(g) = -393.5 kJ/mol