The two columns in the following floor framing plan support…

The two columns in the following floor framing plan support only loads from a bowling alley on the second floor. The city has approved floor live load reductions for this particular building. A dead load of 12.7 psf acts on the tributary area of the columns. Combine this with the reduced floor live load, and then determine the total load that acts on one of the columns.

A wood member is loaded as shown. Using ASD, determine the a…

A wood member is loaded as shown. Using ASD, determine the adjusted bending strength, Fb’. Assume normal temperatures, no incising, and that all loads act in the directions shown. Ignore the weight of the member.Load:PD = 1,000 lbPL = 0 lbPLr = 0 lbPS = 0 lbPR = 0 lbPW = 7,500 lbPE = 5,000 lbQD = 1,500 lbQL = 3,500 lbQLr = 4,500 lbQS = 500 lbQR = 1,000 lbQW = 0 lbQE = 0 lbSpan:L = 12 ft Member size:4 x 6 Stress grade and species:Select Structural Douglas Fir-Larch Unbraced length:lu = 0 ft Moisture content:MC > 19 percent 

A wood member is loaded as shown. Using ASD, determine the m…

A wood member is loaded as shown. Using ASD, determine the maximum axial stress in the member. Assume normal temperatures, no incising, and that all loads act in the directions shown. Ignore the weight of the member.Load:PD = 2,500 lbPL = 0 lbPLr = 0 lbPS = 0 lbPR = 0 lbPW = 9,000 lbPE = 6,500 lbQD = 2,000 lbQL = 2,500 lbQLr = 1,000 lbQS = 2,000 lbQR = 1,000 lbQW = 0 lbQE = 0 lbSpan:L = 10 ft Member size:4 x 10 Stress grade and species:No. 1 Douglas Fir-Larch Unbraced length:lu = L/2 = 5 ft Moisture content:MC < 19 percent 

Determine the ASD adjusted design compression strength paral…

Determine the ASD adjusted design compression strength parallel to grain, Fc’, for the following beam. Assume normal temperatures, bending about the strong axis, and no incising. Ignore the weight of the beam.Load:wD = 200 lb/ftwLr = 330 lb/ftLoad combination:D + LrSpan:L = 6 ftMember size:4 x 10Stress grade and species:Select Structural Douglas Fir-LarchUnbraced length:lu = 0Moisture content:MC < 19 percentLive load deflection limit:Allow. Δ ≤ L/360