Notice: Function _load_textdomain_just_in_time was called incorrectly. Translation loading for the jwt-auth domain was triggered too early. This is usually an indicator for some code in the plugin or theme running too early. Translations should be loaded at the init action or later. Please see Debugging in WordPress for more information. (This message was added in version 6.7.0.) in /home/forge/wikicram.com/wp-includes/functions.php on line 6121
Notice: Function _load_textdomain_just_in_time was called incorrectly. Translation loading for the wck domain was triggered too early. This is usually an indicator for some code in the plugin or theme running too early. Translations should be loaded at the init action or later. Please see Debugging in WordPress for more information. (This message was added in version 6.7.0.) in /home/forge/wikicram.com/wp-includes/functions.php on line 6121 Order: Inderal 30 mg p.o. q.i.d. Supply: Indernal 20 mg tabl… | Wiki CramSkip to main navigationSkip to main contentSkip to footer
15 pоints Online Editоr Link (Fоrk this): LINK Alternаtively, you cаn аlso use the editor here: LINK Write a function sum_nested_structure(data) that takes a single parameter data which can be a deeply nested structure containing integers, lists, and dictionaries. The function should calculate and return the sum of all integers found within this structure. If a dictionary is encountered, sum the values stored in it. Assume that the keys for dictionaries will be strings only. Note: You can determine if value is a list with type(value) == list or if it is a dictionary with type(value) == dict. Example: print(sum_nested_structure(42))# Output: 42 print(sum_nested_structure([1, 2, 3, 4]))# Output: 10 print(sum_nested_structure([1, [2, 3], 4]))# Output: 10 print(sum_nested_structure({"a": 1, "b": 2, "c": 3}))# Output: 6 print(sum_nested_structure([1, {"a": 2, "b": [3, 4]}, 5]))# Output: 15 print(sum_nested_structure([1, ["hello", 2], {"a": 3, "b": ["world", 4]}]))# Output: 10 Additional Examples: nested_data = { "a": 5, "b": [1, 2, {"x": 3, "y": [4, 5]}], "c": {"d": 6, "e": [7, {"f": 8}]} } print(sum_nested_structure(nested_data)) #Output: 41 ----------- nested_data = [ { "a": 10, "b": 12, "c": 14 }, [1, 5, 8], 5 ] print(sum_nested_structure(nested_data)) #Output: 55