Suppose that you have eight cards. Five are green and three…
Suppose that you have eight cards. Five are green and three are yellow. The cards are well shuffled.Suppose that you randomly draw two cards, one at a time, without replacement.G1 = first card is greenG2 = second card is greenFill in the tree diagram chart of the situation. Odds of each color for 1st Card (fraction)First Card drawnG(reen) or Y(ellow)Letter for color Followed by 1Odds of each color for 2nd Card(fraction)Second Card DrawnLetter for color Followed by 1Set of Cards DrawnG(reen) or Y(ellowLetter for first card’s color followed by second letter for second colorG2(G,G)□ / □G1□ / □□ / □StartY2(G,Y)G2(Y,G)□ / □□ / □Y1□ / □Y2(Y,Y) Find P(G1 AND G2) (both green) Find P(at least one green). Note another way of saying this might be what is 1 (which represents 100%) less the probability of the cards both being yellowFind P(G2|G1). This is the probability of the second card being green given that the first was green. Are G1 and G2 independent events?No, they are dependent, because the probability of the second draw changes based on the first draw. Yes, they are independent, because the first card is already gone before the second draw.Yes, they are independent, because both events are “drawing a green card.”No, they are dependent, because independent events must happen at the same time.