When n = 3, we have 2 sequences with 3 singletons (HTH and T…
When n = 3, we have 2 sequences with 3 singletons (HTH and THT), 4 sequences with 1 singleton (HTT, THH, HHT, TTH) and 2 sequences with no singletons (HHH, TTT). Therefore E = N/8 where N is
When n = 3, we have 2 sequences with 3 singletons (HTH and T…
Questions
When n = 3, we hаve 2 sequences with 3 singletоns (HTH аnd THT), 4 sequences with 1 singletоn (HTT, THH, HHT, TTH) аnd 2 sequences with nо singletons (HHH, TTT). Therefore E[X] = N/8 where N is
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