A student reacted 3.05 grams of K2Cr207 with 11.2 grams of o…
A student reacted 3.05 grams of K2Cr207 with 11.2 grams of oxalic acid and 3.82 grams of potassium oxalate. All contain waters of hydration as indicated by the formulas in the lab. Calculate the theoretical yield of product, in moles. K2Cr207(aq) +7 H2C2O4(aq) +2 K2C2O4(aq) → 2 K3•3H2O(s) + 6 CO2(g) + H2O(l) MW K2Cr207 =294.19 g/mol MW oxalic acid = 126.07 g/mol MW potassium oxalate= 184.23 g/mol