Uncle John was running late for work on Monday morning and decided to use Highway 407 (toll highway) to save time during morning rush hour traffic. The 407 toll highway charges a fee for traveling on this road. There is a fixed cost of $5.10 and a variable charge of $0.41 per km traveled. a) Write a cost equation that can be used to determine the Cost “C”, to travel a distance “d” kilometres on the 407.hint: you can model this equation using the basic formula y = mx + b b) Uncle John entered onto this toll highway and traveled approximately 33 km until exiting. Using your formula from above, determine how much it will Cost ($) him to drive on this road? c) Approximately how many kilometres did he travel on the 407 if his bill was $32.00
For the given functions f and g , find the indicated composi…
For the given functions f and g , find the indicated composition. f(x) = 4×2 + 5x + 4, g(x) = 5x – 5 (g ∘ f)(x).
Use the definition of inverses to determine whether f and g…
Use the definition of inverses to determine whether f and g are inverses., g(x) =
For the pair of functions, find the indicated sum, differenc…
For the pair of functions, find the indicated sum, difference, product, or quotient, and give the domain of the new function. f(x) = x2 + 1, g(x) = 5x – 8Find (f g)(x).
y = x2 + 8
y = x2 + 8
For the pair of functions, find the indicated sum, differenc…
For the pair of functions, find the indicated sum, difference, product, or quotient, and give the domain of the new function. f(x) = 9x – 5, g(x) = 5x – 2Find (f – g)(x).
Find the requested function value.Find (f ∘ g)(2) when f(x)…
Find the requested function value.Find (f ∘ g)(2) when f(x) = 8x + 9 and g(x) = 8×2 – 2x – 6.
f(x) = x2 + 7x – 4
f(x) = x2 + 7x – 4
For the given functions f and g , find the indicated composi…
For the given functions f and g , find the indicated composition. f(x) = 3x + 10, g(x) = 4x – 1 (f ∘ g)(x)
From a Graph: A line moves down 3 units for every 4 units it…
From a Graph: A line moves down 3 units for every 4 units it moves to the right. The slope is: