Is this population at Hardy-Weinberg equilibrium? AA A…
Is this population at Hardy-Weinberg equilibrium? AA Aa aa 0.49 0.42 0.09 p = 0.7; q = 0.3 Hint: remember that under Hardy Weinberg equilibrium, p2+ 2pq +q2= 1. You can use the allele frequencies p (frequency of A) and q (frequency of a) to find the expected frequencies of genotypes AA, Aa, and aa under Hardy-Weinberg. If these expected frequencies match the frequencies you actually see above, it is in HW equilibrium.