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The ESE for a particular exposure is 1.1 mGy, what will be t…

The ESE for a particular exposure is 1.1 mGy, what will be the intensity of the scattered beam perpendicular to and 1 m from the patient?

The ESE for a particular exposure is 1.1 mGy, what will be t…

Posted on: December 2, 2025 Last updated on: December 2, 2025 Written by: Anonymous Categorized in: Uncategorized
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